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Question about course - Switching Power Supply Design Course

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  • robertferanec
    1. Yes, you are right and also as mairomaster explained, DNF = Do Not Fit this component
    2. Very good question. Basically, it is not described directly in datasheet, but for very small currents you can use VCC pin (the pin 3, signal +5V_VCC) as source of 5V
    3. The polygon is +5V_VCC.

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  • mairomaster
    I realised I have the project available.

    I don't have much information about the design, but on a first look it seems that PVCC can be connected to either LDO, VIN or 5V_VCC. By default it is connected to LDO by R1. The L4 plygon is connecting all 5V_VCC nodes.

    Robert will be able to explain much better, since he designed the circuit. I don't have much free time, so I can't check the datasheet of the IC.

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  • Eoliveira
    commented on 's reply
    Hello mairomaster,

    Could I send to you my project by email ?

    Thank you very much for your support.
    Have a nice day

  • mairomaster
    You are correct - DNF means do not fit. You can also see it by DNP (do not populate) or NF (no fit). I don't have the schematics at the moment to answer the rest of the questions.

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  • Question about course - Switching Power Supply Design Course

    Hello Everyone.

    Can you help me, please ?

    I'm trying understand a detail in our schematic...
    1. What means "DF" under componnent symbol in our schematic ? I think that when my board will go to manufacture that componnent won't be assembled. Am I correct? Is it an optional componnent to another configuration to power supply?
    2. About the Layer 4 (Polygon). If I Dont't have in my board the following componnent ( DNF - R2 = 10R )... How the signal +5V_LDO will go to L4 (Polygon) ?
    3. Is +5V_LDO and + 5VCC the same signal on L4 ( Polygon )?